3a^2-[7a^2-2a-3(a^2-a)+1]先去括号,再合并同类项
- 教育综合
- 2024-05-15 12:59:49
先化简,再求值;3a的2次方-中括号7a的2次方-3(a的2次方-a)+1中括号
3a的2次方-中括号7a的2次方-3(a的2次方-a)+1中括号 =3a^2-[7a^2-3(a^2-a)+1] =3a^2-[7a^2-3a^2+3a+1] =3a^2-[4a^2+3a+1] =3a^2-4a^2-3a-1 =-a^2-3a-12a∧2+(3a∧2-2a)-3(a∧2-a )先去括号,再合并同类项 要过程哦
=2a²+3a²-2a-3a²+3a =(2a²+3a²-3a²)+(-2a+3a) =2a²+a先去括号,在合并同类项. (3a^2-b^2)-3(a^2-2b^2)
(3a^2-b^2)-3(a^2-2b^2) =3a^2-b^2-3a^2+6a^2 =5a^2先化简,再求值:3a2-7a+[3a-2(a2-2a-1)],其中a=-2
3a2-7a+[3a-2(a2-2a-1)]
=3a2-7a+3a-2a2+4a+2
=a2+2,
当d=-2时,原式=4+4=8.
(3a05-7a)-2(a05-3a+2)
去括号,合并同类项: (3a^2-7a)-2(a^2-3a+2) =3a^2-7a-2a^2+6a-4 =a^2-a-4。展开全文阅读